Answer:
Periodic
Step-by-step explanation:
Because the terms repeat, this is a periodic sequence.
Answer: 2x^2
The three terms are
2x^2
-3x
5
as they are separated by a plus sign. You can think of it as 2x^2 + (-3x) + 5 if you want. The quadratic term is the term with the exponent of 2
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
C. 0, 1.29, -0.65
Step-by-step explanation:
The real solutions of the equation 
is where the graph of 
intersects the x-axis.
This means that we need to graph using a graphing software.
From the graph shown in the attachment 
, 
, and 
are the real solutions.
The correct choice is C
First arrange numbers
14,15,15,17,19,20,21,23,24
19 is median
15+15/2=15 is first quartile
