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2 years ago

What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 42°?

Mathematics

1 answer:

blsea [12.9K]2 years ago

3 0

Answer:

96 degrees

Step-by-step explanation:

you have two angles that each measure 42 degrees, giving you 84 degrees combined

there are 180 degrees in a triangle, therefore the vertex angle is equal to 180 minus 84, or 96 degrees

check:

42 + 42 + 96 = 180

180 = 180

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Arrange the steps from start to finish to factor this expression using the grouping method x^2-5x-24 drag the tiles to the corre

rosijanka [135]

Answer:

(x - 8)(x + 3)

Step-by-step explanation:

x² - 5x - 24

Consider the factors of - 24 which sum to give the coefficient of the x- term (- 5)

The factors are - 8 and + 3 , since

- 8 × + 3 = - 24 and - 8 + 3 = - 5

Use these factors to split the x- term

x² - 8x + 3x - 24 ( factor the first/second and third/fourth terms )

= x(x - 8) + 3(x - 8) ← factor out (x - 8) from each term

= (x - 8)(x + 3) ← in factored form

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3 years ago

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Nataly [62]

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3 years ago

Write the equation of the conic section with the given properties:

timurjin [86]

Answer:

$\frac{x^2}{64} + \frac{y^2}{25} =1$

Step-by-step explanation:

An ellipse with vertices (-8, 0) and (8, 0)

Distance between two vertices = 2a

Distance between (-8,0) and (8,0) = 16

2a= 16

so a= 8

Vertex is (h+a,k)

we know a=8, so vertex is (h+8,k)

Now compare (h+8,k) with vertex (8,0) and find out h and k

h+8 =8, h=0

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a minor axis of length 10.

Length of minor axis = 2b

2b = 10

so b = 5

General formula for the equation of horizontal ellipse is

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b} =1$

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$\frac{(x-0)^2}{8^2} + \frac{(y-0)^2}{5} =1$

$\frac{x^2}{64} + \frac{y^2}{25} =1$

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2 years ago