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SSSSS [86.1K]
3 years ago
11

What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 42°?

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

96 degrees

Step-by-step explanation:

you have two angles that each measure 42 degrees, giving you 84 degrees combined

there are 180 degrees in a triangle, therefore the vertex angle is equal to 180 minus 84, or 96 degrees

check:

42 + 42 + 96 = 180

180 = 180

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a - 2

Step-by-step explanation:

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side 3 = 6a - 2a - 3a + 3 - 6 + 1 = a - 2

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3 years ago
The board of a large company is made up of 7 women and 9 men. 6 of them will go as a delegation to a national conference.
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Answer:

a) 5765760

b) 60480

c) 5705280

Step-by-step explanation:

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n=\frac{16!}{(16-6)!}=16*15*14*13*12*11\\ n= 5765760

b) How many of these delegations have all men?

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c) How many of these delegations have at least one woman?

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4 0
3 years ago
Please help me. I need help please.
Mice21 [21]

Answer:

The correct options are;

EFGH has 4 congruent sides

Diagonal FH bisects angles EFG and EHG

Angle FEH is congruent to angle FGH

Step-by-step explanation:

1) Given that for a reflection, we have;

The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection

Therefore;

The distance of the point E from the line HF = The distance of the point G from the line HF

Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)

We can show that from the length of a line given by the equationl = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}, that the length EH ≅ GH and EF ≅ GF

Therefore since we are given that EH = EF, we have;

EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides

2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;

ΔEHF ≅ ΔGHF

∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent

Similarly, ∠GFH ≅ ∠EFH

Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF

Therefore, diagonal FH bisects angles EFG and EHG

3) Given that ΔEHF ≅ ΔGHF, we have;

Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent

7 0
3 years ago
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