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klasskru [66]
3 years ago
10

Find the integer less than 3 and greater than 4​

Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

{x : x ε Z where x<3 & x>4}

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Solve the following system of linear equations by graphing:<br> 2x + 2y = 10<br> 8x + 8y = 24
andriy [413]

Answer:

Step-by-step explanation:

-8x - 8y = -20

8x + 8y = 24

0 ≠ 4

2y = -2x + 10

y = -x + 5

8y = -8x + 24

y = -x + 3

inconsistent

7 0
3 years ago
a large cheese pizza coast $7.50. each additional topping for the pizza costs $1.35. if the total bill for the pizza sally order
Orlov [11]

Answer:

She ordered 4 toppings.

Step-by-step explanation:

7.5+1.35x=12.90

1.35x=12.9-7.5

1.35x=5.4

x=5.4/1.35

x=4

6 0
4 years ago
Read 2 more answers
Please help, been struggling with this for almost a week now.
nikitadnepr [17]

Answer:

A \approx 1140.3\ units^2

Step-by-step explanation:

To solve this problem we first need to find the diameter of the circle. We are told the point N is the circle, so we can assume it is the center of the circle. To find the diameter we can use the Pythagorean Theorem:

a^2 + b^2 = c^2\\40^2 + 9^2 = c^2\\1600 + 81 = c^2\\1681 = c^2\\\sqrt{1681} = c\\41 = c

The diameter is 41 units, which means the radius is \frac{41}{2}. From here we can calculate the area of the circle:

A_c = \pi r^2\\A_c = \pi (\frac{41}{2})^2\\A_c = \pi 420.25\\A_c \approx 1320.25

Now we need to subtract the area of the triangle from the area of the circle. Calculate the area of the triangle:

A_t = \frac{bh}{2}\\A_t = \frac{40 \times 9}{2}\\A_t = \frac{360}{2}\\A_t = 180

Subtract the triangle area from the circle area to get the area of the shaded area:

A = A_c - A_t\\A = \pi420.25 - 180\\A = 1140.25431\\A \approx 1140.3\ units^2

5 0
2 years ago
Michael cleans 90 cars in 5 days. How many cars does Michael clean per day?
Neko [114]

Answer:

18

Step-by-step explanation:

Since he does 90 cars-----5 days

x cars--------1 day

we multiply 90 by 1 then over 5

5 0
2 years ago
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Pleaseeee help asappppppp
lord [1]

Answer:

ED = 12

<em><u>HOPE </u></em><em><u>THIS </u></em><em><u>HELP </u></em><em><u>YOU </u></em><em><u>,</u></em><em><u> </u></em><em><u>FOR </u></em><em><u>ANY </u></em><em><u>QUESTION </u></em><em><u>PLEASE </u></em><em><u>ASK </u></em><em><u>ME </u></em><em><u>.</u></em>

7 0
2 years ago
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