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3 years ago

15

Estimate the slope of the tangent line of the function y(t)=\sqrt{(3t+1} at the point t=2.

1 answer:

Korvikt [17]3 years ago

7 0

Answer: 0.567

Step-by-step explanation:

$y(t)=\sqrt{3t+1} \\\\y'(t)=\dfrac{3}{2\sqrt{3t+1} } \\\\y'(2)=\dfrac{3}{2\sqrt{3*2+1} } =\dfrac{3\sqrt{7} }{14} =0,56694670951384084082177480435127\approx{0.567}$

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You synthetic division to find P(3) for p(x)=x^4-6x^3-4x^2-6x-2

klio [65]

By the polynomial remainder theorem, the remainder upon dividing $p(x)$ by $x-3$ will be the value of $p(3)$ .

... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137

So you have

$\dfrac{x^4-6x^3-4x^2-6x-2}{x-3}=x^3-3x^2-13x-45-\dfrac{137}{x-3}$

which means $p(3)=-137$ .

5 0

3 years ago

Y=2 Enter the solution (x, y) to the system of equations shown 7y+3x=5

AnnyKZ [126]

Answer:

(x, y) = (-3, 2)

Step-by-step explanation:

Put the given value of y into the equation and solve for x.

... 7·2 +3x = 5

... 3x = -9 . . . . . . subtract 14

... x = -3 . . . . . . . divide by the x-coefficient

The solution (x, y) is (-3, 2).

6 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers

1. Create shapes of the given perimeter. Label all sides.

KonstantinChe [14]

Step-by-step explanation:

It looks like you have to draw a figure and then label every side with how long it is.

This first shape is a pentagon because it has 5 sides, and for each side of the pentagon the length would be 3/5 so .6 inches.

The second shape is a square because it has 4 sides, you than would label each side as 1 ft, because when you add them all it equals 4.

The third shape is a triangle with 3 equal sides. When you divide 16.8/3 it shows thag each side of this triangle will be labeled with 5.6 meters.

8 0

3 years ago

A theater has 33 seats in the first row, 37 seats in the second row. 41 seats in the third row, and so on. How many seats are th

Jlenok [28]

Answer:

90 seats are in row 19

Step-by-step explanation:

The pattern is adding 4 seats so 3 x 19 is 57 so 33 + 57 is 90 seats

Hope this helps

5 0

1 year ago