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klasskru [66]
3 years ago
6

Solve each equation r-38=9

Mathematics
2 answers:
LuckyWell [14K]3 years ago
7 0
We start with r-38=9
 So in this case we are solving for r.
 You want to get the variable (r) by itself so you'll add 38 to 9
         r-38=9
          +38 +38
So 9+38 is 47. 
R by itself is equivalent to 1r so 47/1 is 47
   Therefore, r=47
Slav-nsk [51]3 years ago
5 0
R is equal to 47. U have to add the 9 and 38 to find what R represents. U wellllccccoooommmmmeeee
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Does anyone know this ? Thank you
alina1380 [7]

Answer:

36

Step-by-step explanation:

angle ACB = 180-130=50 degree

angle ABC = 180 - (94+50)

                  = 180-144

                  = 36

6 0
3 years ago
A triangle has an area of 160 square inches. If it has a height of 10 inches, what is its base length?
inn [45]

Answer:

The answer is:

32 inches

Step-by-step explanation:

The reason to why is because a triangle's area is always length times height divided by 2. In this case we need to reverse the steps and multiply 160 by 2 to get 320. Then divide the area of 320 by 10 to get 32 inches to be the base length.

Hope you have a wonderful day :)

6 0
3 years ago
Jada paints a circular table that has a diameter of 44 inches. What is the area of the table? Round to the nearest whole number!
Elza [17]

Answer: 1521

Step-by-step explanation: use the equation pi times radius square. Your radius is always going to be half your diameter so you'll use 22 instead. Then plug that I'm and you should get 1520.53 rounded would be 1521.

5 0
3 years ago
Read 2 more answers
Among two supplementary angles, the measure of the larger angle is 44°
zhuklara [117]

Answer:

68° and 112°

Step-by-step explanation:

Supplementary angles sum to 180°

let the smaller angle be x then the larger angle is x + 44 , then

x + x + 44 = 180 , that is

2x + 44 = 180 ( subtract 44 from both sides )

2x = 136 ( divide both sides by 2 )

x = 68

Smaller angle = 68° and

larger angle = x + 44 = 68 + 44 = 112°

6 0
2 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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