2 years ago

I need help please help m

Mathematics

1 answer:

Bond [772]2 years ago

5 0

there are 10 numbers you want either a 4 or 7 ( 2 numbers)

so probability is 2/10 which reduces to 1/5

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Solve the question that you posed in Part 1. Show all of your steps in answering the question.

Sergeu [11.5K]

Answer:

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3 years ago

The first term of a geometric sequence is –2 and the common ratio is -1/-4. What are the next three terms of the sequence?

masha68 [24]

-2 * 1/4 = -1/2
-1/2 * 1/4 = -1/8
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Correct choice is the first one.

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The sum of two numbers is 15, and the sum of their square is 137. What are the numbers?

Verdich [7]

Answer:

11 and 4

Step-by-step explanation:

11 squared plus 4 squared = 137

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7 0

3 years ago

I NEED HELP PLEASEEE

Gwar [14]

Answer:

b = $\sqrt{333}$

Step-by-step explanation:

1. We can use the Pythagorean Theorem to find the missing side, b.

$14^2 + b^2 = 23^2$

2. (Solving)

Step 1: Simplify both sides of the equation.

$(14*14)+b^2 =(23*23)$
$196 + b^2 = 529$

Step 2: Subtract 196 from both sides.

$196 + b^2 - 196 = 529 - 196$
$b^2 = 333$

Step 3: Take square root of both sides.

$\sqrt{b^2} = \sqrt{333}$
$b = \sqrt{333}$

Step 4: Check if solution is correct.

$14^2 + \sqrt{333^2} = 23^2$
$(14*14)+(\sqrt{333} *\sqrt{333})=23*23$
$196 + 333 = 529$
$529 = 529$

Therefore, b = $\sqrt{333}$ .

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2 years ago

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Step-by-step explanation:

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