Y = - 5 x + 10
A ) x = - 15, y = 5
5 = 75 + 10
5 ≠ 85
B ) x = 2, y = 0
0 = - 5 · 2 + 10
0 = 0 ( correct )
C ) x = - 1, y = - 5,
- 5 = 5 + 10
- 5 ≠ 15
D ) x = 3, y = 25
25 = - 15 + 10
25 ≠ - 5
Answer:
B ) ( 2, 0 )
I do believe it is 12 as well considering the fact that it's negative three and not positive. If it was a positive three then maybe it would be 18.
Answer and Explanation:
Number of classes = 8
Highest value =2300
Lowest value = 1250
Class width= highest value – lowest value / number of classes
= 2300 – 1250/8
= 131.25 = 132
So, we can write class as 1250+132=1382
Class frequency
1250-1382 2
1382-1514 3
1514-1646 6
1646-1778 2
1778-1910 3
1910-2042 2
2042-2174 1
2174-2306 1
If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 
then
will also be a solution.