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scoundrel [369]
3 years ago
8

Can someone explain how 8.75 multiplied by 0.8 is 7??? It just don't make sense... I don't see why the number got smaller instea

d of bigger.....
Mathematics
2 answers:
vovangra [49]3 years ago
5 0

Answer:

It's because of the decimal of .8

Step-by-step explanation:

It can be confusing but since its not a whole number when you multiply with a whole number gets smaller instead of bigger. So the whole number basically has to give some of it to the decimal so, that the outcome can be a whole number.

Sorry, if this isn't the best!

yarga [219]3 years ago
3 0

Answer:

80% of 8.75=7. I'm pretty sure this is the reason.

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Art [367]

The anwser is A: 6.67. you are welcome!


8 0
4 years ago
Please help me with #5 !?
Anastaziya [24]

Answer:

4/15

Step-by-step explanation:

to find out the portion that is shaded we can do the following:

1 - (1/3 + 2/5)

now we want a common denominator, we can use 15:

15/15 - (5/15 + 6/15)  →  15/15 - 11/15

the answer is 4/15

4 0
3 years ago
Read 2 more answers
Can someone help me with this please!!
Elenna [48]

Step-by-step explanation:

part A

all listed features (A - F) are correct and to be selected.

part B

the average rate of change is

(f(x2) - f(x1)) / (x2 - x1)

so,

(f(0) - f(-2)) / (0 - -2) = (2 - 0) / (0 + 2) = 2/2 = 1

8 0
2 years ago
The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
FrozenT [24]

Let Y_i denote the number of packages brought by customer i. If, for instance, X=2 customers are in line, then the total number of packages is Y=Y_1+Y_2, and

P(Y=y)=P(Y_1=y_1,Y_2=y_2)=P(Y_1=y_1)P(Y_2=y_2)

since the number of packages brought by any customer is independent from the number of packages brought by any other.

a. P(X=3,Y=3) is the probability that a total of 3 packages are waiting to get wrapped from among a total of 3 customers. This means each customer must have exactly one package. So

P(X=3,Y=3)=P(X=3)P(Y=3)^3\approx0.0416

b. P(X=4,Y=11) is the probability that a total of 11 packages are brought by 4 customers. The only way for there to be 11 packages is if 3 customers bring 3 packages and the last 1 brings 2. There are \dbinom43=4 ways this can happen, so

P(X=4,Y=11)=4P(X=4)P(Y=3)^3P(Y=2)\approx0.0002

6 0
3 years ago
Find the value of tan30+cot30+sin60​
Aliun [14]

Hello!

This is a problem about relating values of the Unit Circle.

First, we need to figure out the specific "points" of each angle measure of 30 and 60.

For the angle measure 30, the point will be (\frac{\sqrt{3}}{2},\frac{1}{2}).

For the angle measure 60, the point will be (\frac{1}{2},\frac{\sqrt{3}}{2}).

The tangent value of a point will be its y value over its x value.

\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{2}*\frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}

The cotangent value of a point will be the reciprocal of the tangent value, which we found previously.

\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}

The sine value of a point will be the y value of the point.

\frac{\sqrt{3}}{2}

So the values we have so far are \frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}

Now we have to find the LCD to add these together, which in this case would be 6.

\frac{2\sqrt{3}}{6}+\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}

Which adds up to \frac{11\sqrt{3}}{6}, which is in simplest radical form.

Hope this helps!

8 0
3 years ago
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