Answer:
A bird drops a stick to the ground from a height of 80 feet. The equation 0=−16x2+64x+80 gives the number of seconds that have passed when it hits the ground. After about how many seconds did the stick hit the ground?
Step-by-step explanation:
h = -16t^2 + 80 Stick hits the ground when h = 0:
0 = -16t^2 + 80
16t^2 = 80
t^2 = 80/16 = 5
t = POSITIVE root 5 (due to the real world nature of the problem)
t approximately 2.236 seconds.
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Graph is a downward opening parabola with h-intercept of 80, t-intercept(s) of sqrt(5), - sqrt(5)
Symmetric about h-axis, though I would only graph on the right side of the h-axis since
that is where t >= 0.
Answer:
Step-by-step explanation:
Using soh cah toa
Sin=opp/hot
Sin 52°=h/121
h=sin52°×121
h=0.7880×121feet
h=95.348feet
44 is 16% of 275. 275 times 0.16 is 44
we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
