SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get
|f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
-0.4 < x - 2 < 0.4
-0.4+2 < x < 0.4+2
1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
</span>
Answer: number 5 is A number 6 is B
Step-by-step explanation:
.04b is 2% of 2b because .04 multiplied by 100 is 4 then you divide by 2 which gets you 2.
.04/2=x/100
cross multiply and divide
it is 98% smaller than 2b.
.2b is 10% of 2b because .2 multiplied by 100 is 20 then you divide by 2 and get 10.
.2/2=x/100
it is 90% smaller than 2b.
.56b is 28% of 2b because .56 multiplied by 100 is 56 then divide by 2 and you get 28.
.56/2=x/100
it is 72% smaller than 2b.
1.8b is 90% of 2b because 1.8 multiplied by 100 is 180 then divide it by 2. you get 90.
1.8/2=x/100
it is 10% smaller than 2b.
2.5b is 125% of 2b because 2.5 multiplied by 100 Is 250 and 250 divided by 2 is 125.
2.5/2=x/100
it is 25% larger than 2b
3b is 150% of 2b because 3 multiplied by 100 is 300 and 300 divided by 2 is 150.
3/2=x/100
it is 50% larger than 2b
87b-179+957/87 = 180
33b12 = 1584
b2+120 = 128
51b - 24 = 180
So the answer are the first one and the last one :)))
