Using row 4:
<span>coefficients are: 1, 4, 6, 4, 1 </span>
<span>a^4 + a^3b + a^2b^2 + ab^3 + b^4 </span>
<span>Now adding the coefficients: </span>
<span>1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 </span>
<span>Substitute a and b: </span>
<span>a = 4x </span>
<span>
b = -3y </span>
<span>1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 </span>
<span>Now simplify the above: </span>
<span>256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4 </span>
Step-by-step explanation:
x² + 3 / x - 1 = x + 1
- x² - x
------------
0 x + 3
- x - 1
-------------
0 4
the remainder is 4
Area is 6000 yd2
LW = 6000
field must be 40 yards longer than its width
L = W + 40
Replace L with W+40 in 1st equation to solve for Width
(W+40)(W) = 6000
W2 + 40W - 6000 = 0
This is a quadratic but is factorable
Factors of -6000 that add to 40 are (100)(-60)
(W+100)(W-60) = 0
W = -100 or W = 60
Since the width will not be negative discard -100
The width is 60 yards
Length is W+40 = 100 yards
The mass in kg is 106.27 if the mass of a cube, M (kg), is proportional to the cube of the length of its edge, L(m).
<h3>What is a proportional relationship?</h3>
It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.
We have:
The mass of a cube, M (kg), is proportional to the cube of the length of its edge, L(m).
M ∝ L³
After removing proportional sign
M = cL³
Plug M = 50 kg and L = 70 cm = 0.7 m
50 = c(0.7)³
c = 145.77 kg/m³
If L = 0.9 m, then M
M = (145.77 kg/m³)(0.9 m)³
M = 106.266 ≈ 106.27 kg
Thus, the mass in kg is 106.27 if the mass of a cube, M (kg), is proportional to the cube of the length of its edge, L(m).
Learn more about the proportional here:
brainly.com/question/14263719
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