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4 years ago

Question is on picture

Mathematics

2 answers:

Artemon [7]4 years ago

6 0

The answer is 9 so D

Westkost [7]4 years ago

3 0

Answer:3

Step-by-step explanation:

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What is the solution? 21=42−3r r=−8 r=−7 r = 7 r = 8

faltersainse [42]

R=-7, you have to put each answer in the equation, therefore; 21=42-3(-7) So you have to do multiplication (PEMDAS, if you arent aware of that acronym then it stands for the order of what to do with an equation, Parentheses get solved first, then Exponents, then multiplication, then division, then addition, then finally subtraction. Solving in that order will solve your answer correctly.) With -3 times -7 which gives you 21. Then you do 42 - 21 which equals 21. So 21 = 21.

7 0

3 years ago

Read 2 more answers

Which inverse operation would be used to verify the following equation? 102 ÷ 3 = 34

IRISSAK [1]

The answer would be 102/34 = 3

7 0

3 years ago

Read 2 more answers

3 pounds of bananas cost $7. At this rate, how much does 1 pound of bananas cost?

Furkat [3]

Answer:

Step-by-step explanation:

To find the cost of 1 pound of bananas we use ratio and proportion

From the question

3 pounds of bananas costs $7

Then 1 pound will cost

$\frac{7 \times 1}{3} = \frac{7}{3 } \\ = 2.33333...$

We have the final answer as

Hope this helps you

7 0

3 years ago

4. If the figures below are similar with a scale factor<br> of 2:3, find the value of x.

Kobotan [32]

Answer:

x = 63

Step-by-step explanation:

Using proportion to solve for x

$\frac{42}{x}$ = $\frac{2}{3}$ ( cross- multiply )

2x = 126 ( divide both sides by 2 )

x = 63

4 0

3 years ago

1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.

Elza [17]

This ODE is separable, so you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2}{x^3}\iff\dfrac{\mathrm dy}{y^2}=\dfrac{\mathrm dx}{x^3}$

Integrating both sides gives

$-\dfrac1y=-\dfrac1{2x^2}+C$

and given the initial condition $y(1)=1$ , you have

$-\dfrac11=-\dfrac1{2(1)^2}+C\implies C=-\dfrac12$

so that the solution is

$-\dfrac1y=-\dfrac1{2x^2}-\dfrac12\implies y=\dfrac1{\frac1{2x^2}+\frac12}=\dfrac{2x^2}{1+x^2}$

4 0

4 years ago