Let x be the unknown number.
7x + 668 < 2000 => 7x plus 668 is less than 2000
where:
7x => x represents the number of cans to be collected in 7 days
668 is the number of cans already collected.
2000 is the target number of cans.
7x + 668 < 2000
<u> - 668 -668</u>
7x < 1332
<u>÷7 ÷7</u>
x < 190.30
or
x < 190
To check:
7x + 668 < 2000
7(190) + 668 < 2000
1330 + 668 < 2000
1998 < 2000
X=2 so 2+4=6 so y=6. I just gone ovee this unit aswell.
Answer:
Step-by-step explanation:
The coefficients of the quadratic x^2 + 7x + 3 are a = 1, b = 7 and c = 3.
The discriminant is b^2 - 4ac, or 49 - 4(1)(3), or 49-12, or 37.
Because the discriminant is positive, we know that this quadratic equation has two real, different solutions.
-7 ± √37
x = --------------- => x = (-7 + √37)/2 and x = (-7 - √37)/2
2
In words: This quadratic equation has two real, unequal solutions involving the radicand 37.
The professional runner can run 4 1/6 miles in 30 minutes.
Since the professional can run 1 1/4 times as far in 30 minutes, we multiply 3 1/3 by 1 1/4:
(3 1/3)(1 1/4)
Convert each to an improper fraction (multiply the whole number by the denominator and add the numerator):
10/3(5/4) = 50/12 = 25/6 = 4 1/6.
