Make 2 equations one for the price and one for quantity. so first set x = AA and y= AAA. for price 37= 1x+.75y. now for the quantity we have x+y=42. Now we can solve by subtracting the equation for price from the equation for quantity and we get .25y =5. solving this we get y= 20. Now we plug that value back in and solve for x. 22 double A's and 20 triple A's.
Answer:
k = 10
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ ZYM is an exterior angle of the triangle, thus
4k + 5 + 6k + 10 = 115, that is
10k + 15 = 115 ( subtract 15 from both sides )
10k = 100 ( divide both sides by 10 )
k = 10
Answer: Hello your question is poorly written attached below is the complete question
answer:
![y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-11%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]](https://tex.z-dn.net/?f=x%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%5C%5C12%5C%5C-40%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
![y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]](https://tex.z-dn.net/?f=y%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C-11%5C%5C5%5Cend%7Barray%7D%5Cright%5D)
![x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]](https://tex.z-dn.net/?f=x%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%5C%5C12%5C%5C-40%5Cend%7Barray%7D%5Cright%5D)
attached below is the detailed solution using LU factorization