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Svetach [21]
2 years ago
10

Find the slope of the line represented by the table of values.

Mathematics
2 answers:
olga55 [171]2 years ago
7 0

Answer:

the answer is 2.5

Step-by-step explanation:

Colt1911 [192]2 years ago
3 0

Answer:

9/2 or4.5

Step-by-step explanation:

(2,8) (4,13)

y2-y1/x2-x1=m

13-8/4-2/=9/2

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A shop is having a sale all items are reduced work out the sale price of an item normally priced at £60
Naddik [55]

Question:

A shop is having a sales all items are reduced by 25%. Work out the sale price of an item normally priced at £60?

Answer:

The new price is £45

Step-by-step explanation:

Given

Sales\ price = \pounds 60

Rate = 25\%

First, calculate the reduction

Reduction = Rate * Sales\ price

Reduction = 25\% * \pounds 60

Reduction = \pounds 15

The new price is:

New = Sales\ price - Reduction

New = \pounds 60 - \pounds 15

New = \pounds 45

3 0
3 years ago
Can someone help me on Domain and Range
egoroff_w [7]

Answer:

Its the second option.

Step-by-step explanation:

The domain and range are just the x (domain) and y (range) values

8 0
3 years ago
Correct Answers only please! I only have two attempts on this assignment, and I cannot retake it. I've already tried the answer
Strike441 [17]

Answer: A. x= 5"

Step-by-step explanation:

ORIGINAL/NEW = 11"/7" = 8.5"/x

x = 7" x 8.5"/11" = 59.5"/11 = 5.409 ≅ 5.41"

If we wanted to keep most of the engraving, we would adjust the larger dimension, but we have been asked to adjust one dimension to 5", since it is said that C. x = 5.41 is incorrect

Then we will adjust

ORIGINAL/NEW = 11"/y = 8.5"/5"

y= 11" x 5"/8.5" = 6.47"

Then the new dimensions of the paper are 6.47" x 5" to fit an 7" x 5" frame

Answer: A. x= 5"

\textit{\textbf{Spymore}}

4 0
3 years ago
Read 2 more answers
Round to the nearest thousandth, Height 8 cm and radius 2cm
Vesna [10]

Answer:

125.660 cm^2

Step-by-step explanation:

Surface area of a right cylinder is A=2πrh+2πr^2

π= 3.14

h= 8 cm

r= 2 cm

A=(2)(3.14)(2)(8) + (2)(3.14)(2)^2

8 0
3 years ago
The rectangle below has an area of 30k^3 +6k^2 square meters. The width of the rectangle (in meters) is equal to the greatest co
Debora [2.8K]

Answer:

The width = 6k^2 m and the  length = 5k + 1 m.

Step-by-step explanation:

The GCF of 30k^3 and 6k^2 is 6k^2.

Width = 6k^2 (answer).

The length = area / width

=  (30k^3 + 6k^2)  / 6k^2

= 5k + 1  (answer).

5 0
3 years ago
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