Answer:
Step-by-step explanation:
Given:
for x≤1400; N = 5
So, Δx = =∑C(a + nΔx).Δx
=C(0)Δx + C(280)Δx + C(560)Δx + C(840)Δx + C(1120)Δx
= Δx[C(0) + C(280) + C(560) + C(840) + C(1120)]
= 280[49 + 42.616 + 34.664 + 25.144 + 14.056]
=280[165.48]
=46334 approx
Answer:
Step-by-step explanation:
Given : In a state where license plates contain six digits.
Probability of that a number is 9 = [Since total digits = 10]
We assume that each digit of the license number is randomly selected .
Since each digit in the license plate is independent from the other and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.
Binomial probability formula:
, where n= total trials , p = probability for each success.
Let x be the number of 9s in the license plate number.
Then, the probability that the license number of a randomly selected car has exactly two 9's will be :
Hence, the required probability = 0.098415