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pychu [463]
3 years ago
13

The total expenditures on benefits​ (in billions of​ dollars) can be approximated by the function h(x)=23.5(1.08)x​, where x​ =

5 corresponds to the year 1995. ​(a) What was the amount for total expenditures in 2011​? ​(b) What was the first full year in which expenditures exceeded ​$110 ​billion?
Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0
Sorry don’t know but good luck
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How do I solve this math problem?
Nat2105 [25]

Answer: 4x² + 4x - 2 - \frac{3}{2x+3}

<u>Step-by-step explanation:</u>

You can use either synthetic or long division.  I am using synthetic division:

2x + 3 = 0   ⇒   x = -\frac{3}{2}

 -\frac{3}{2}   |    4    10    4    -6

       <u>|    ↓    -6    -6    3 </u>

            4     4    -2   -3  ← <em>-3 is the remainder</em>

            ↓     ↓     ↓

           4x² +4x  -2  ← <em>factored polynomial</em>

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3 years ago
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3 years ago
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Felipe set his watch 2 seconds behind, and it falls behind another 1 second every day. How many days has it been since Felipe la
umka21 [38]

Answer:

49 days

49 days

8 0
2 years ago
A person places $262 in an investment account earning an annual rate of 3.7%,
yaroslaw [1]

Answer:

$315.24

Step-by-step explanation:

Principal, P =$262

Rate, r= 3.7% =0.037

Time, t= 5 Years

The Value of the Investment which is compounded continuously is gotten using the formula:

V=Pe^{rt}\\=262*e^{0,037*5}\\=\$315.24

The value of the investment after 5 years is $315.24 to the nearest cent.

3 0
3 years ago
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Anna11 [10]

Answer:

Domain → (-∞, ∞)

Range → (-∞, ∞)

Step-by-step explanation:

Domain of a function is defined by the x-values or input values of the graph.

Similarly, Range of the function is defined by the y-values or output values from the graph.

From the picture attached,

x - values for the line shown in the graph vary from negative infinity to positive infinity.

Therefore, Domain of the function will be → (-∞, ∞)

And for every x-value there is a y-value, so Range of the function will be same as domain (varying from negative infinity to positive infinity) → (-∞, ∞)

8 0
3 years ago
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