1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pychu [463]
3 years ago
13

The total expenditures on benefits​ (in billions of​ dollars) can be approximated by the function h(x)=23.5(1.08)x​, where x​ =

5 corresponds to the year 1995. ​(a) What was the amount for total expenditures in 2011​? ​(b) What was the first full year in which expenditures exceeded ​$110 ​billion?
Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0
Sorry don’t know but good luck
You might be interested in
√6 + √30 <br><br> √36 + √36<br><br> √ - Square Root<br><br> Pls help :(
slavikrds [6]
The square root of 6 is 2.44 +
Square root of 30 is 5.47
So 2.44 + 5.47 is 4.01
Your answer is 4.01

Square root of 36 is 6
So 6+ 6 is 12
Your answer is 12


Hope this helps *smiles*
8 0
2 years ago
Will mark brainliest!! factor the following equation: g(x)=2x²-2x-24​
Darina [25.2K]

Answer:

g(x)=2(x-4)(x+3)​

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the missing value: x2 (squared) = 625 5 10 25 50
Alona [7]

\bf x^2=625\implies x=\sqrt{625}\implies x=25

5 0
3 years ago
Read 2 more answers
Write the number 21, 473, 862, 095 in word form.
ipn [44]

Answer:

C. twenty one billion, four hundred seventy three million, eight hundred sixty two thousand, and ninety five

Step-by-step explanation:

please mark brainliest, give a thanks, and rate a five stars if this helped! feel free to ask anymore questions if you need any more help! thanks!

(lol optional): add my sc: tealyn337

8 0
2 years ago
Read 2 more answers
A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
EleoNora [17]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

b) P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

c) P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

d) E(X) = 20*0.2= 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

P(X=4)

And using the probability mass function we got:

P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

3 0
2 years ago
Other questions:
  • What is the area of a triangle with a base of 2 5/8 mm and a height of 10 mm?
    15·1 answer
  • Consider the figure. What is the value of x?
    5·1 answer
  • Help with any please ?
    8·1 answer
  • 5) 5x-4= 20<br> у = 3х - 12<br> solve
    13·1 answer
  • Select all solutions to the equation (2. — 4)(x + 5) = 0.
    14·1 answer
  • Please pe please please please please please help me
    7·1 answer
  • What is true about the isosceles trapezoid?
    11·1 answer
  • A sports team came to town. the stadium filled all 10,000 seats at two-level pricing. level 1 tickets are $50 each, and level 2
    7·1 answer
  • Find the domain and the range of the relation. Determine whether the relation is a function.
    5·1 answer
  • A 9-foot piece of ribbon costs $20.07. What is the price per yard?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!