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3 years ago

The formula for the surface area of a cylinder with radius r and height h is at times twice the product of the

Mathematics

1 answer:

MrMuchimi3 years ago

6 0

Answer:

<em> $2\pi \: rh + 2\pi {r}^{2} = 2(t \times {r}^{2} )$ </em>

Step-by-step explanation:

The TSA of the cylinder

$2\pi \: rh + 2\pi {r}^{2}$

In Mathematics, 'is' is =

Twice means 2( )

Product means ×

So we have

$2\pi \: rh + 2\pi {r}^{2} = 2(t \times {r}^{2} )$

as the answer.

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7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

Juliette [100K]

Answer:

A) JK and AB =

$[tex] \boxed{( \theta) = \f{12}{( \theta)} }$ So, =》 $\dfrac{10}{5} = \dfrac{1}{ \( \theta) }$ =》 $\( \theta) = \dfrac{5}{2}$ [/tex]

B) AABC

$[tex] \boxed{( \theta) = {1}{( \theta)} }$ So, $23}{-18=\\Ans } \boxed$

C) AABM:

$[tex] e \fbox{: }$ The value of k for which $\sin(jm) = \cos(x)$ is $\dfrac{\p}{2}$ ans[/tex]

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3 years ago

The city of Omaha decided to build a new parking garage in hopes of luring more people to the Old Market district.The city will

dimulka [17.4K]

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

$= \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645$

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

$CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}})$

$CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}})$

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

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3 years ago

Let x and y be any numbers at all with x ≤ y. Show that the number of integers between x and y is [y] - [x] +1.That is show that

ddd [48]

Answer:

the explanation is given below.

Step-by-step explanation:

Here what is applied is assumption of range of values of number from say 1 - 100

In total, i stopped at 100 on the dot.

from this, the lowest number is 1 and the highest number is 100

hence the range of the numbers = Difference between Highest and Lowest

range = 100 - 1 = 99, the 99 gotten as the range is indicative that a number has been missing.

In order to make up the 100, an integer is added to the difference = 99, i.e 99 is added to 1 to make up the 100.

Furthermore, if 0 is exclusively out when numbers are counted up 100 with 0 inclusive, in such case, the first and last number are excluded from the counting. as such the integers will be {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.........., 99} since both 0 and 100 are not included.

Here, if we try to get the range = highest - lowest = 99 - 1 = 98, it implies that to make up the 99, an integer is added to the result of the difference = 98+1 = 99

As such, the number of integers between two numbers is the difference between the highest and the lowest number plus 1 i.e highest - lowest + 1 = y - x +1 = (the floor of y) - ( the ceiling of x) + 1

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3 years ago

Which set of numbers is a geometric sequence?

Andreyy89

I believe the answer is the second option because they are all divisible by 4. Hope i helped.
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3 years ago

Read 2 more answers

Plz show work, NEED HELP FAST PLZ

OLga [1]

Answer:

5. 4 6. 6