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atroni [7]
3 years ago
8

Please please help help

Mathematics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

7

Step-by-step explanation:

35/5

divide the 5 d's by the longest piece of tape.

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What is the sum of the first six terms of the geometric series? 2 – 6 18 – 54 ...
Law Incorporation [45]

The sum of the first six terms of the geometric series is -364.

A geometric series is a sequence of terms in a fixed common ratio.

Apparently, the expression "geometric progression" comes from the "geometric mean" (Euclidean term) of segments of lengths a and b: it is the length of the side c of a square whose area is equal to the area of ​​the rectangle. a and b. May

The series given is

2 – 6 + 18 – 54 + ...

The sum of n terms of a geometric series is given by

Sn=a1 * 1 - rn/1 - r

here the first term is 2

r = -6 /2 = -3

S = 2 (1-(-3)⁶)/(1-(-3))

S = -364

Therefore the sum of the First six terms of the geometric series is -364 .

Learn more about geometric series here:brainly.com/question/24643676

#SPJ4

6 0
2 years ago
Can you help me with this? 7
andrezito [222]

Answer:

65º

Step-by-step explanation:

  • The angle of a straight line is 180º, so ∠ABD=180º and ∠ABC=(180-6x)º
  • The sum of the interior angles of a triangle is 180, so (x+40)º+(3x+10)º+(180-6x)º=180
  • We can solve from there, x+40+3x+10+180-6x=180
  • Combine like terms, -2x+230=180
  • Subtract 230, -2x=-50
  • Divide by -2, x=25
  1. m∠CAB=(x+40)º=(25+40)º=65º
  2. m∠ABC=(180-6x)º=(180-150)º=30º
  3. m∠BCA=(3x+10)º=(75+10)º=85º
4 0
3 years ago
Any of these questions will be ok
Alekssandra [29.7K]
#7:

It means to solve for y.


#8:

We can write:

l = w + 2

Because it says the length is 2 more than the width.


3 0
3 years ago
Can someone please help me? I keep losing points...
Setler79 [48]

Answer:

14,400

Step-by-step explanation:

i=prt

p=40,000

r=0.09 have to turn percent to decimal

t=4

(40,000)(0.09)(4)

7 0
4 years ago
Read 2 more answers
Find the absolute maximum and absolute minimum values of f on the given interval.
anyanavicka [17]

The question is missing parts. Here is the complete question.

Find the absolute maximum and absolute minimum values of f on the given interval.

f(x)=xe^{-\frac{x^{2}}{32} } , [ -2,8]

Answer: Absolute maximum: f(4) = 2.42;

              Absolute minimum: f(-2) = -1.76;

Step-by-step explanation: Some functions have absolute extrema: maxima and/or minima.

<u>Absolute</u> <u>maximum</u> is a point where the function has its greatest possible value.

<u>Absolute</u> <u>minimum</u> is a point where the function has its least possible value.

The method for finding absolute extrema points is

1) Derivate the function;

2) Find the values of x that makes f'(x) = 0;

3) Using the interval boundary values and the x found above, determine the function value of each of those points;

4) The highest value is maximum, while the lowest value is minimum;

For the function given, absolute maximum and minimum points are:

f(x)=xe^{-\frac{x^{2}}{32} }

Using the product rule, first derivative will be:

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} )

f'(x)=e^{-\frac{x^{2}}{32} }(1-\frac{x^{2}}{16} ) = 0

1-\frac{x^{2}}{16}=0

\frac{x^{2}}{16}=1

x^{2}=16

x = ±4

x can't be -4 because it is not in the interval [-2,8].

f(-2)=-2e^{-\frac{(-2)^{2}}{32} }=-1.76

f(4)=4e^{-\frac{4^{2}}{32} }=2.42

f(8)=8e^{-\frac{8^{2}}{32} }=1.08

Analysing each f(x), we noted when x = -2, f(-2) is minimum and when x = 4, f(4) is maximum.

Therefore, absolute maximum is f(4) = 2.42 and

absolute minimum is f(-2) = -1.76

8 0
3 years ago
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