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Juliette [100K]
3 years ago
9

Find the angles between -pi and pi that satisfy: (−√3) sin(v)+cos(v)=√3

Mathematics
1 answer:
MAXImum [283]3 years ago
3 0

Observe that

\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v

In the original equation, divide both sides by \dfrac12:

-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2

\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2

Next,

\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi

where n is any integer. Then

\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi

Fix n=0 to ensure -\pi, so that

v=-\dfrac\pi6,v=-\dfrac\pi2

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