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quester [9]
2 years ago
10

Which part of a resume gives an account of past jobs and internships?

Computers and Technology
1 answer:
kirill [66]2 years ago
5 0

Answer:

Internships section above your Work History section

Explanation:

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What is modularity? Help asap
mash [69]

I believe it is b “Broadly speaking, modularity is the degree to which a system's components may be separated and recombined, often with the benefit of flexibility and variety in use. ... However, the concept of modularity can be extended to multiple disciplines, each with their own nuances.”

4 0
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The shortest compressed format of the ipv6 address 2001:0db8:0000:1470:0000:0000:0000:0200 is
devlian [24]

The answer is : 2001:DB80:1470::200

A double colon ( :: ) can replace any single, contiguous string of one or more 16-bit segments (hextets) which is  consist of all 0s, and it can only be used once per IPv6 address. Therefore,any leading 0s (zeros) in any 16-bit section or hextet can be omitted.

3 0
3 years ago
How do you change the top and bottom margins of an entire document?
Firdavs [7]

Answer:

Click the Page Layout tab and then the Margins button.

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Explanation:

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4 0
3 years ago
Read 2 more answers
What type of windows network model allows all the participants to be represented equally on the network with no single computer
noname [10]
The workgroup as a type of windows network model allows all the participants to be represented equally on the network with no single computer having authority or control over another. The workgroup is peer-to-peer local area network. 
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4 0
3 years ago
For a new version of processor, suppose the capacitive load remains, how much more energy will the processor consume if we incre
erastovalidia [21]

Answer:

The answer is below

Explanation:

The amount of power dissipated by a processor is given by the formula:

P = fCV²

Where f = clock rate, C = capacitance and V = Voltage

For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:

P(old) = fCV²

For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:

P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor

Hence, the new processor is 1.728 times (72.8% more) the power of the old processor

4 0
3 years ago
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