After looking at your question, I reasoned you were writing this in python. Here's my code, I hope it helps!
while True:
v1 = input("Enter value of first variable (T/F) ")
v2 = input("Enter value of second variable (T/F) ")
v3 = input("Enter value of third variable (T/F) ")
print("v1: {}, v2: {}, v3: {} = T".format(v1, v2, v3) if v1 == "T" and v2 == "T" or v1 == "T" and v3 == "T" else "v1: {}, v2: {}, v3: {} = F".format(v1, v2, v3))
Answer:
The correct answer is option (D) Identify the impact on safety of the property
Explanation:
Solution
In every Business Impact Analysis, the first and the most important step is for the CISO is to identify and estimate the impact of the aftereffects on the business and property of an organization that may be occurred from the disaster.
Physical security is very important, but it is not noticed by most organizations. It is important if you do not want anyone to take away your information or destroy it, in case of natural calamity. the reason could be that, the intruder is doing it for his personal achievement, financial gain,or seeking revenge or when one is taken unaware and becomes a target. If this security is not maintained properly all the safety measures will not be useful once the attacker gets through by gaining physical access.
Example of property can be software, equipment, facilities, company’s assets.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
