Answer:
A. False
C. False
B. False
D. True
Step-by-step explanation:
Frequency histogram is denote the actual frequency of each observation or different class- intervals whereas Relative frequency distribution shows the fraction of that frequency to the total frequencies or the percent of that frequency to the total.
Thus the shape of both histogram are same.
A. False.
C. False
Since, Scale of the y-axis is different. But they has same shape.
B. False
Since, vertical scale is different for both histogram and horizontal scale is same.
D. True
Answer:
- the point
- the line
- the plane
Step-by-step explanation:
:D
I think it would just me 20 +72m, since it is already simplified
For this case we have the following functions:
We must find 
By definition of composition of functions we have:
So:
![(p-9) (x) = x ^ 2-1- [5 (x-1)] = (x ^ 2-1) -5 (x-1)](https://tex.z-dn.net/?f=%28p-9%29%20%28x%29%20%3D%20x%20%5E%202-1-%20%5B5%20%28x-1%29%5D%20%3D%20%28x%20%5E%202-1%29%20-5%20%28x-1%29)
Thus, the correct option is option C.
Answer:
Option C
The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.
Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s
Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s
t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.
Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time = 1.065 s (nearest thousandth)
