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balandron [24]
3 years ago
8

Which set is a function?

Mathematics
2 answers:
7nadin3 [17]3 years ago
6 0
An input can have two outputs but, an output cannot have two inputs. So, D is right.
seraphim [82]3 years ago
5 0
It has to be "D" :)


hope it helped1
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If a punch bottle says 20% fruit juice,and it is a 200 milliliter bottle, how many milliliters of fruit juice is in the bottle?
padilas [110]

Answer:

There are 40 milliliters of fruit juice in the bottle

Step-by-step explanation:

we know taht

20%=20/100=0.20

To find out the milliliters of fruit juice, multiply the volume of the bottle by the percentage of fruit juice in decimal form

so

200(0.20)=40\ ml

therefore

There are 40 milliliters of fruit juice in the bottle

8 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
This is problem six of the homework that you ask for
Marina86 [1]
This equation could represent the relationship e=8.75h
8 0
3 years ago
A colony of bacteria is growing exponentially according to the function below, where t is in hours. How many bacteria are there
pychu [463]
The growth of the bacteria is expressed as:

<span>B(t) = 4 e^0.8t
</span>
where t is the time in units of hours. If the bacteria is allowed to grow for 8 hours then the number of bacteria present would be,


<span>B(t) = 4 e^0.8(8)
</span><span>B(t) = 2407</span>
5 0
3 years ago
Read 2 more answers
Help me out pleaseeee
Kryger [21]

Answer:

The correct option is (b).

Step-by-step explanation:

The solution of the given polynomial is :

(-\dfrac{1}{3},4)

x = 1/3 and y = -4

i.e.

Sum of roots = (1/3-4) = -11/3

Product of roots = (1/3)(-4) = -4/3

The quadratic equation is as follows :

x^2+(\text{sum of roots})x+\text{Product of roots}=0

Put all the values,

x^2+\dfrac{-11}{3}x+\dfrac{-4}{3}=0\\\\3x^2-11x-4=0

So, the correct option is (b).

4 0
3 years ago
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