Question

Factor each completely x^3^a -27y^6^BPls need helpFrom: Brainly.ph (Philippine's)​

Answer 1

Answer:

$= ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b} )$

Step-by-step explanation:

${x}^{3a} - 27 {y}^{6b}$

$( {x}^{a} {)}^{3} - {3}^{3} \times ( {y}^{2b} {)}^{3}$

$( {x}^{a} {)}^{3} - (3 {y}^{2b} {)}^{3}$

$( {x}^{a} - {3y}^{2b} ) \times (( {x}^{a} {)}^{2} + {x}^{a} \times {3y}^{2b} + ( {3y}^{2b} {)}^{2} )$

$\boxed{\green{= ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b})}}$