A photographer has 591 photos of animals and 234 photos of plants. He wants to put all of the photos into photo books. Each page
2 answers:
Answer:
He could use 104 pages in the photo books .
Step-by-step explanation:
Given :
A photographer has 591 photos of animals and 234 photos of plants.
Each page of the photo books holds 8 photos.
To Find : Fewest number of pages he could use in the photo books.
Solution :
A photographer has 591 photos of animals and 234 photos of plants.
Thus total no. of photos he have = 591+234 = 825 photos
Since he wants to put all the photos into photo book
No. of pages required for 8 photos = 1
No. of pages required for 1 photo = 1/8
No. of pages required for 825 photos:
=
⇒103.125 pages ≈ 104 pages
Hence he could use 104 pages in the photo books .
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Answer:
Test statistic (t-value) of this one-mean hypothesis test is -2.422.
Step-by-step explanation:
We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.
We have to test if the amount of TV in New York City is less than the national average.
Let Null Hypothesis, :
3 {means that the amount of TV in New York City is less than the national average}
Alternate Hypothesis, :
> 3 {means that the amount of TV in New York City is more than the national average}
The test statistics that will be used here is One-sample t-test statistics;
T.S. = ~
where, = sample mean time = 2.5 hours per week
= sample standard deviation = 0.09 hours
n = sample size = 19
So, <u>test statistics</u> = ~
= -2.422
Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.