Answer:
![\mathbf{\dfrac{\pi}{6}[5 \sqrt{5}-1]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cdfrac%7B%5Cpi%7D%7B6%7D%5B5%20%5Csqrt%7B5%7D-1%5D%7D)
Step-by-step explanation:
Given that:
The surface area (S.A) 
Hence the S.A is of form z = f(x,y)
Then the S.A can be represented with the equation
where :
D = cylinder 
In polar co-ordinates:
D = {(r, θ): 0≤ r ≤ 1, 0 ≤ θ ≤ 2π)
Similarly, 
and 
Therefore;
![= [\theta]^{2 \pi}_{0} \dfrac{1}{8}\times \dfrac{2}{3}\begin {bmatrix} (1+4r^2)^{\dfrac{3}{2}}\end {bmatrix}^1_0](https://tex.z-dn.net/?f=%3D%20%5B%5Ctheta%5D%5E%7B2%20%5Cpi%7D_%7B0%7D%20%5Cdfrac%7B1%7D%7B8%7D%5Ctimes%20%5Cdfrac%7B2%7D%7B3%7D%5Cbegin%20%7Bbmatrix%7D%20%281%2B4r%5E2%29%5E%7B%5Cdfrac%7B3%7D%7B2%7D%7D%5Cend%20%7Bbmatrix%7D%5E1_0)
![= 2 \pi \times \dfrac{1}{12}[5^{\dfrac{3}{2}} - 1]](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%20%5Cdfrac%7B1%7D%7B12%7D%5B5%5E%7B%5Cdfrac%7B3%7D%7B2%7D%7D%20-%201%5D)
![\mathbf{=\dfrac{\pi}{6}[5 \sqrt{5}-1]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%3D%5Cdfrac%7B%5Cpi%7D%7B6%7D%5B5%20%5Csqrt%7B5%7D-1%5D%7D)
Answer:
I put a pic, i hope ill help :)
No.
The only value that can be put in K that would have the same zeros would be 4 but 4 is not an odd integer. If there was an odd integer that the sum and product would be the same then it would lie on the x-axis. but only 4 fits the criteria.
Answer:
the third option
Step-by-step explanation:
do you want an explanation?
M is 6 more than 10 so it will be 16
