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larisa86 [58]
3 years ago
12

Knowing that the result of expanding (x+a)(x-6) is x²+mx-48, find the values ​​of a and m.​

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0

We know -48 came from (a)(-6), the "L" in "FOIL".

If -48 = -6a, then a = 8.

Now with a=8, go ahead and FOIL (x+8)(x-6) to find m.

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Write x^3/2 in radical form
stiv31 [10]

Answer:

Step-by-step explanation:

I think you meant x^(3/2).  This breaks down in at least two ways:

[x^3]^(1/2), or √(x^3)m or √x³), or

[x^(1/2)]^3 = (√x)^3

3 0
3 years ago
What is the inverse of the function fx) x +3?
xz_007 [3.2K]
<span>My answer -
f(x)=x^3+2 To find the inverse function f(x)^-1 , we will assume" y=x^3+2 y-2= x^3 ==> x= (y-2)^1/3 ==> f(x)-1= (x-2)^1/3</span>
P.S

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6 0
3 years ago
Find the intersection point between the lines of equations:<br><br>2x-y+6=0 and 2x+3y-6=0 ​
Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0

On subtracting the given equations we have,

\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3

Put this value in any equation , we have ,

\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5

Hence the lines will Intersect at ,

\implies\underline{\underline{ Point=(-1.5, 3)}}

8 0
3 years ago
Read 2 more answers
What is the answer 101/8+(35/8+27/8
suter [353]

Answer:

\frac{163}{8}

Step-by-step explanation:

The sum already has common denominators so there is no need to change the denominators. Just add the numerators.

\frac{35}{8} + \frac{27}{8} = \frac{62}{8}

\frac{101}{8} + \frac{62}{8} = \frac{163}{8}

4 0
4 years ago
Read 2 more answers
The class​ ________ is the​ breadth, or​ range, of numbers we plan to put into each class of a frequency distribution using grou
NikAS [45]

Answer:

Width

Step-by-step explanation:

When we have quantitative data it is grouped in classes. There are three ways in which the data can be grouped they are:

Single value grouping where each class has one distinct value.

In Cutpoint grouping is used when the observations have decimal points

In Limit grouping a classes are set based on a specified range of values. Here limit grouping is being done and the range of each class is called width.

4 0
3 years ago
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