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larisa86 [58]
2 years ago
12

Knowing that the result of expanding (x+a)(x-6) is x²+mx-48, find the values ​​of a and m.​

Mathematics
1 answer:
Citrus2011 [14]2 years ago
6 0

We know -48 came from (a)(-6), the "L" in "FOIL".

If -48 = -6a, then a = 8.

Now with a=8, go ahead and FOIL (x+8)(x-6) to find m.

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I hope this I better than the blurry photo I took '-'​
Black_prince [1.1K]

Answer:The fourth option

decreases by 1 minute every 2 hours trained

Step-by-step explanation:

If y is how much it decreses its negative, and if the slope is -1/2 then they decrease by one for every 2 hours since the two represents x.

7 0
2 years ago
11. Solve the linear inequality.
Mkey [24]

Answer:

Your answer is E

Step-by-step explanation:

Here you go mate

Step 1

-17x+2<-10x-19  Equation/Question

Step 2

-17x+2<-10x-19  Simplify

-7x<-21

Step 3

−7x<−21 Use 7 to divide

answer

So therefore x>3

7 0
3 years ago
Counselors at Rockport High School and Riverdale High School surveyed the graduating seniors to find out their post-high-school
siniylev [52]

The percentage shows that they were 28% more likely to come from Riverdale High school.

<h3>How to calculate the percentage?</h3>

From the information given, the percentage of those from Rockport will be:

= 25/(25 + 44) × 100.

= 25/69 × 100

= 36.23%

The percentage of those from Riverdale will be:

= 44/(25 + 44) × 100.

= 44/69 × 100

= 63.77%

Therefore, the difference will be:

= 63.77% - 36.23%

= 28% approximately.

Learn more about percentages on:

brainly.com/question/24304697

3 0
2 years ago
Suppose that for a certain experiment p​(b​)equals=0.5 and p​(avertical line upper bb​)equals=0.2. find p​(aintersect∩b​).
raketka [301]
P(a | b) = p(a ∩ b)/p(b) . . . . . a definition worth remembering
0.2 = p(a ∩ b)/0.5 . . . . . . . . fill in the given values
0.2*0.5 = 0.1 = p(a ∩ b)

p(a ∩ b) = 0.1
5 0
3 years ago
What is the equation of the line that passes through the point (2,7) and has a slope of 6?
Mumz [18]

Answer:

y= 6x - 5

Step-by-step explanation:

3 0
3 years ago
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