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pickupchik [31]
3 years ago
15

The question plz help

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).

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