We will have that for the previous year, he had in the account:

For the year previous to that one, he had:

For the previous year to that, he had:

For the year previous to that one, he had:

For the second year that the money was in the account, there was:

And the orinial ammount of money that was in the account was:

From this, we know that Jhon had originally $1400.37 in the bank account.
Answer: t= 3/2
Step-by-step explanation: 5/ 7 1/2 = 3/2
Answer:
C. y = x² - 6x + 10
Step-by-step explanation:
Formula f(x)=a(x-h)^2+k (h,k) is vertex
Y=a (x-3)^2+1
Plug in y intercept
10=a (0-3)2+1
10=-3^2a+1
10=9a+1
9=9a
A=1
Y=(x-3)2 +1
Y=x2-6x+9+1
Y=x2-6x+10
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