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34kurt
2 years ago
15

Don’t skip this question i have a test plz answer

Mathematics
2 answers:
Gwar [14]2 years ago
6 0
Bottle A-7
Bottle B-4
labwork [276]2 years ago
6 0
It would be 3 because bottle a would be 8
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Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (1,2). A. Y=2x^2. B. Y=
Aleonysh [2.5K]
General equation of parabola:  y-k = a(x-h)^2

Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2

All we have to do now is to find the value of the coefficient a.

(1,2) is on the curve.  Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.

The equation of this parabola is y = 2x^2.
5 0
2 years ago
Factor the following:<br><br> x2−6x+5
lukranit [14]

Answer:

the 6x element as there is no solution in integers.

Step-by-step explanation:

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3 years ago
Hi<br> khgbv h<br> ljv nkmj<br> gv hnyhrdsrfgbnkjnbhbbbhjik
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7 0
2 years ago
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Given h(x) = 4x + 3, find h(-1)<br>​
dsp73

Answer:

-1

Step-by-step explanation:

4x-1=-4

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7 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
3 years ago
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