8.7 _____ 8.5<br> ><br> <<br> =<br> which one this is a quiz for you!

If the dimensions of a rectangular prism are 39 mm × 12 mm × 15 mm, then what is the surface area

grin007 [14]

Answer:

$\huge\boxed{SA=2466\ (mm^2)}$

Step-by-step explanation:

The formula of a Surface Area of a rectangular prisms:

$SA=2(lw+lh+wh)$

<em>l</em><em> - length</em>

<em>w</em><em> - width</em>

<em>h</em><em> - height</em>

<em />

We have:

$l=39mm;\ w=12mm;\ h=15mm$

Substitute:

$SA=2\bigg((39)(12)+(39)(15)+(12)(15)\bigg)\\\\SA=2(468+585+180)\\\\SA=2(1233)\\\\SA=2466\ (mm^2)$

5 0

3 years ago

A market buys watermelons for $1.25 they want to make a 20% profit what should they charge for the watermelons

Serhud [2]

Answer: $1.50

Step-by-step explanation:

Cost price of watermelon = $1.25

Profit percent = 20%

Profit = Profit percent × Cost price

= 20% × $1.25

= 20/100 × $1.25

= 0.2 × $1.25

= $0.25

Selling price = Cost price + Profit

Selling price = $1.25 + $0.25

Selling price = $1.50

They should charge $1.50 for the watermelons

6 0

3 years ago

5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes

snow_tiger [21]

Answer:

<h3>The value C(t) of the car after 5 years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after 5 years:</h3>

Initial value $C(0)= $16,000$

Depreciation rate is $r=\frac{4.5}{100}$

Period , t=5 years

$C(t)=C(0)(1-r)^t$

Substitute the values we get

$C(5)=16000(1-0.045)^5$

$=16000(0.955)^5$

$=16000(0.7943)$

∴ $C(5)=12708.8$

<h3>The value C(t) of the car after 5 years is $ 12709</h3>

3 0

3 years ago

The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam

katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.93}{2} = 0.035$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.035 = 0.965$ , so $z = 1.81$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when $M = 1$ . We have that $\sigma = \sqrt{39}$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}$

$\sqrt{n} = 1.81\sqrt{39}$

$(\sqrt{n})^2 = (1.81\sqrt{39})^2$

$n = 127.8$

Rounding up

A sample size of 128 is needed.

7 0

3 years ago

Find f(7). f(x)=x^2+9<br><br> Find b(-2)-a(12). a(x)=13x-2;b(x)=8x-14

baherus [9]

Answer:

f(7)=58

b(-2)-a(12)=-188

Step-by-step explanation:

f(7)=(7)^2+9

49+9

f(7)= 58

b(-2)-a(12)=8(-2)-14-13(12)-2

-16-14-156-2

=-188

4 0

3 years ago

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8.7 _____ 8.5 > < = which one this is a quiz for you!