Question

A certain material decays at a rate 0.92% per year. How much of 260 grams of the material will be left in 11years ?

Answer 1

A= p (1-r)^t
A material after 11 years
P current amount 260
R rate of decreases 0.0092
T time 11 years

A=260×(1−0.0092)^(11)
A=234.87 round
A=235