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3 years ago

An area of a triangle is 30cm^2. Side c is 2x + 3 and side b is 4x + 5. The only angle is angle A, 30°. What is the value of x?

Mathematics

1 answer:

Sever21 [200]3 years ago

3 0

Answer: x = 3.66666667

Step-by-step explanation:

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If a+1=b then b>a create values for a and b

trapecia [35]

Answer:

One is a = 2, b = 3 AND another one is a = 11, b = 12

Step-by-step explanation:

They all fit this description. b = 1+a

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3 years ago

1.) What is the domain of a function y = x + 3 when the range is {7, 4,3}

mart [117]

Answer:

Step-by-step explanation:

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3 years ago

When h has the value 12 calculate 5h - 2

yarga [219]

Answer:

5h - 2

(5×12)-2

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=58

7 0

3 years ago

Are there any linear quantities in the chart shown? And if so, what is the slope of said pairs?

VashaNatasha [74]

The chart does not represent a linear quantity

<h3>How to determine if there are linear quantities in the chart shown?</h3>

From the chart, we have the following coordinates

(x, y) = (0.10, 0.14), (0.50, 0.32), (1.00, 0.46), (1.70, 0.59) and (2.00, 0.63)

To determine if the chart is a linear quantity, we simply calculate the slope using the coordinates.

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

So, we have:

m = (0.32 - 0.14)/(0.50 - 0.10) = 0.45

m = (0.46 - 0.32)/(1.00 - 0.50) = 0.28

In the above computations, the calculated slopes are not equal

Hence, the chart does not represent a linear quantity

Read more about linear equations at:

brainly.com/question/1884491

#SPJ1

7 0

2 years ago

0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

7 0

3 years ago