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san4es73 [151]
3 years ago
6

A wheel on a piece of machinery makes one revolution every minute (60 seconds.) How many degrees does it move in 10 seconds?

Mathematics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

It moves 6 degrees a second that means it moves 60 degrees in 10 seconds.

Step-by-step explanation:

360/60=6

6x10=60.

360 is how many degrees there are in a second and 60 seconds in a minutes.

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Step-by-step explanation:

Please put a picture

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Andrew walks 2000 feet from his house to his office. What distance does he cover?
Paul [167]
The answer is B. 24,000 in.
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Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
5. Find the sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4
Elza [17]

Answer:

The sum of the first 35 terms of the arithmetic sequence when a = 5 and d = 4 is 2555.

Step-by-step explanation:

Given:

a = 5

d =  4

To Find :

The sum of first 35 terms of the arithmetic sequence  = ?

Solution:

Step 1 : finding the 35th term

a_n = a_1 +(n-1)d

a_35 = 5 +(35-1)4

a_35 = 5 +(34)4

a_35 = 5 +136

a_35 = 141

Step 2: Finding the sum of first 35 terms

S_n = \frac{n(a_1 +a_n)}{2}

Substituting the values

S_n = \frac{35(5+141)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{35(146)}{2}

S_n = \frac{5110)}{2}

S_n = 2555

7 0
4 years ago
No one seems to be he;ping with this question so please help and show proof of how u got the answer
MA_775_DIABLO [31]

Answer:

C = 60t + 70

Step-by-step explanation:

The total cost of hiring Plumbing Service is given by the equation C = 50t + 70, where C is the total cost in dollar and t is the time in hours.

So, $ 70 is the fixed price and $50 is the rate of charge per hour for the service.

Now if in the next month the rate of charge per hour for the service increased to $60 and the initial charge remains the same then the equation for the total cost of hiring Plumbing Service will become C = 60t + 70. (Answer)

4 0
3 years ago
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