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Nady [450]
3 years ago
6

Please help I cant do it and it is super late

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0
The linear relationship should be
AGE
16 ,17 ,18 ,19 ,20

162,171,180,189,198
WEIGHT
His weight should be going up 9 pounds per birthday
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slamgirl [31]

We are given:

3x^3-2x^2

There seems to be nothing I can do to simplify this equation. However, I can factor out an x^2 since they both have at least an x^2. Here is what we get:

x^2(3x-2)

This is in the simplest form I can get into. I cannot do anything more to simplify this expression. This is your final answer.

3 0
3 years ago
Renee is wanting to join a gym.
WINSTONCH [101]
Pumping iron: 10x+90=0
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Hassan writes an algebraic expression with four terms. The x-term has a coefficient of 2 and the z-term has a coefficient of -1.
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5 0
4 years ago
Pair of shoes cost three times as much as a scarf. The total cost of one pair shoes and one scarf is $32. If S represents the co
Mariulka [41]
Let's break down all the information we receive from the question.

One pair of shoes= three times as much as a scarf
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6 0
3 years ago
From a point 100 m from a building the angles of elevation of the top and bottom of a flagpole atop a building are 54.5 degrees
AnnZ [28]

Answer:60ft

Step-by-step explanation:The height of the flagpole is approximately  

60

feet.

Explanation:

Always try to draw a diagram.

enter image source here

We know that there is a right angle between the ground and the building. Therefore, we can use the 3 basic trig ratios instead of the sine or cosine law to solve this problem.

Since the angle in the corner of the larger right triangle measures  

42

˚

, the top angle in this triangle measures  

180

˚

−

90

˚

−

42

˚

=

48

˚

.

By basic trig ratios, we can find the height of the building with the flag pole on top, call it  

H

.

tan

42

˚

1

=

H

500

H

=

500

tan

42

˚

I would keep it in exact form until the last step.

We now devise an expression for the height of the building (without the flag pole). Call it  

a

tan

38

˚

1

=

a

500

a

=

500

tan

38

˚

We can now state that

h

=

H

−

a

h

=

500

tan

42

˚

−

500

tan

38

˚

h

≈

59.559

≈

60

feet

Hopefully this helps!

Answer link

EET-AP

Apr 10, 2017

The flagpole is  

60

f

t

in height to the nearest foot.

Explanation:

1) The flagpole is on top of a building.

2)Angles of elevation both measured from point  

500

f

t

from building

3) Angle of elevation to the top of building is  

38

d

e

g

4) Angle of elevation to the top of flagpole is  

42

d

e

g

The information above will provide us with two right angle triangles, one smaller one inside a larger one.

Both will have a base of  

500

f

t

.

The smaller triangle will have a base angle  

β

of  

38

deg opposite the  

90

deg, and the larger triangle will have a base angle  

β

of  

42

deg.

From this information we can find the heights of the building and the building + pole using the definition of the tangent of the two base angles  

β

:

tan

(

β

)

=

o

p

p

a

d

j

where the  

o

p

p

is the height and the  

a

d

j

is the  

500

f

t

o

p

p

(

b

u

i

l

d

)

=

tan

(

38

)

⋅

(

500

f

t

)

=

390.6

f

t

=

height of building

o

p

p

(

f

l

a

g

)

=

tan

(

42

)

⋅

(

500

f

t

)

=

450.2

f

t

=

height of building + pole

Then to the nearest foot the height of the flagpole is:

450.2

f

t

−

390.6

f

t

=

60

f

t

4 0
3 years ago
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