Answer: 3/4 feet
Step-by-step explanation:Conversion a mixed number 3 5/
12
to a improper fraction: 3 5/12 = 3 5/
12
= 3 · 12 + 5/
12
= 36 + 5/
12
= 41/
12
To find new numerator:
a) Multiply the whole number 3 by the denominator 12. Whole number 3 equally 3 * 12/
12
= 36/
12
b) Add the answer from previous step 36 to the numerator 5. New numerator is 36 + 5 = 41
c) Write a previous answer (new numerator 41) over the denominator 12.
Three and five twelfths is forty-one twelfths
Conversion a mixed number 2 2/
3
to a improper fraction: 2 2/3 = 2 2/
3
= 2 · 3 + 2/
3
= 6 + 2/
3
= 8/
3
To find new numerator:
a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/
3
= 6/
3
b) Add the answer from previous step 6 to the numerator 2. New numerator is 6 + 2 = 8
c) Write a previous answer (new numerator 8) over the denominator 3.
Two and two thirds is eight thirds
Subtract: 41/
12
- 8/
3
= 41/
12
- 8 · 4/
3 · 4
= 41/
12
- 32/
12
= 41 - 32/
12
= 9/
12
= 3 · 3/
3 · 4
= 3/
4
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(12, 3) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 12 × 3 = 36. In the next intermediate step , cancel by a common factor of 3 gives 3/
4
.
Answer:
it's -4
Step-by-step explanation:
hope it helped!!!!!!
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is
With what we have
0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
the answer is 10n-13
Step-by-step explanation:
this is a one step problem, all you need to do is add all the like terms together such as n and 9n and since they are both positives they add up to 10n and then with -10 and -3 they would add together to make -13. thats all there is to it, the answer is 10n-13
