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4 years ago

The domain for the graph (in interval notation) is

Mathematics

1 answer:

Ksenya-84 [330]4 years ago

6 0

Answer:

Domain: [-3, 1]

Step-by-step explanation:

Doman is the set of x-values that can be inputted into function f(x).

We see that our x-values span from -3 to 1. Since both have no holes, they are included in our domain:

[-3, 1] or -3 ≤ x ≤ 1

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Chase bought 5 chicken wings for $9.50. If Chase spent $26.60, how many chicken wings did he buy?

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Find the price of 1 wing:

9.50 / 5 = 1.90 per wing

Divide total spent by price per wing:

26.60 / 1.90 = 14

Answer: 14

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Write an equation in point-slope form of the line that passes through the point (2,−8) and has a slope of 4.

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Answer:

Step-by-step explanation:

point (2,−8) and has a slope of 4.

y1 = -8 & x1 = 2 and m = 4

y - y1 = m(x - x1)

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3 years ago

Please help asap 20 pts + brainliest for right/best answer

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3 years ago

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Saiges spaceship traveled 588 kilometers in 60 seconds. Determine whether or not each spaceship trip below has the same speed as

Fiesta28 [93]

Answer:

Part 1) 441km in 45s --> Has the same speed as Saige's spaceship

Part 2) 215km in 25s --> Does not have the same speed as Saige's spaceship

Part 3) 649km in 110s --> Does not have the same speed as Saige's spaceship

Step-by-step explanation:

The complete question is

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

The speed of Saiges spaceship is equal to

$\frac{588}{60}=9.8\ \frac{km}{sec}$

case 1) we have

441km in 45s

Find out the speed of the spaceship trip

$\frac{441}{45}=9.8\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}$

therefore

Has the same speed as Saige's spaceship

case 2) we have

215km in 25

Find out the speed of the spaceship trip

$\frac{215}{25}=8.6\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

Does not have the same speed as Saige's spaceship

case 3) we have

649km in 110s

Find out the speed of the spaceship trip

$\frac{649}{110}=5.9\ \frac{km}{sec}$

Compare the speed of the spaceship trip with the speed of Saiges spaceship

$5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}$

therefore

Does not have the same speed as Saige's spaceship

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