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Pie
3 years ago
7

3 2 3 +2. overline 3 =

Mathematics
1 answer:
ad-work [718]3 years ago
5 0

Answer:

<h2>5 \frac{29}{30}</h2>

Step-by-step explanation:

3 \frac{2}{3}  + 2.3 =  \frac{11}{3}  +  \frac{23}{10}  =  \frac{110 + 69}{30}   \\  \\ =  \frac{179}{30}  = 5 \frac{29}{30}

#Let'sLearn

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11. find the value of x in the kite below.<br> E<br> (6x + 6)<br> F<br> Р<br> G
cluponka [151]

14.

Step-by-step explanation:

6x+6=90 (being a straight line)

6x=90-6

6x=84

x= 84/6

x=14.

8 0
3 years ago
SOMEONE PLEASE HELP​
-Dominant- [34]

Answer:

15c+3b=66 and 25c+5b=110

Step-by-step explanation:

5 0
3 years ago
Thirty adults were asked how many pets they have had over their lifetime.
madam [21]
The statement that is most likely true is that the median is in the 6-10 interval and the mean is in the 6-10

There were a total of 30 different pieces of data collected, so the 15th and 16th pieces of data that would create the median. Both the 15th and 16th numbers would be in the 6 - 10.

If you find the average of the middle data point in each interval the mean would be approximately 7.2. This is in the 2nd interval (6-10).



4 0
3 years ago
Read 2 more answers
-6.5 = z/3 I’m sooo confused.
OLEGan [10]

Answer: z = -19.5

Step-by-step explanation:

-6.5 = z/3

-19.5 = z                     Multiply 3 to both sides

5 0
3 years ago
Read 2 more answers
Suppose the number of inches of rainfall each year in a city is normally distributed. For a random sample of years, the confiden
quester [9]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Or equivalently:

\bar X \pm ME

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Or equivalently:

\bar X \pm ME

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9

4 0
3 years ago
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