The answer would be 10 since 10 times 5 is 50 and a line equals 180 so the answer is A.10
Answer:
Number of monthly calls = 475
Step-by-step explanation:
Given:
Plan 1 = $30 per month unlimited calls
Plan 2 = $11 + $0.04(per call)
Find:
Number of monthly calls, plan 1 better than plan 2
Computation:
Plan 1 (Cost) < Plan 2 (Cost)
30 < 11 + 0.04(x)
19 < 0.04(x)
475 < (x)
Number of monthly calls = 475
The answers would be (0,10) , (20,0) , and (100,100)
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-

Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
The answer is B.
The shaded area includes points less than the line, and the slope is negative. Also, the Y intercept is positive 5.