Cuanto es "Cinco al cuadrado"?
1 answer:
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Step-by-step explanation:
By arc sum Postulate of a circle:
2 x + 3x + 4x = 360°
9x = 360°
x = 360°/9
x = 40°
3x = 3* 40° = 120°
By inscribed angle theorem:
By tangent secant theorem:
Since, measure of central angle is equal to the measure of its corresponding minor arc.
By angle sum Postulate of a triangle:
Answer: depth = 5 ft
width = 10 ft
length = 40 ft
Step-by-step explanation:
d = depth
width = d + 5
length = d + 36
Volume = length x width x depth = 2000 cf
d(d+35)(d+5) = 2000
d( + 40d + 175) = 2000
d^3 + 40d^2 + 175d = 2000
rewrite in standard cubic polynomial form : ax3 + bx2 + cx + d = 0
d^3 + 40(d^2) + 175d - 2000 = 0
Find the roots of the cubic polynomial:
factors of 2000 are 1, 5, 10 15, 20, etc.
Try the factor 5 first by plugging it in the equation:
5^3 + 40(5^2) + 175(5) - 2000 = 0
Lucky break! No need to find the other roots because they will be negative, and you can't have a negative value for a pool depth.
So, depth = 5 ft
width = 5 + 5 = 10 ft
length = 5 + 35 = 40 ft