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JulijaS [17]
3 years ago
13

5. Ryan Just bought 10 gallons of gasoline, the amount of fuel used for the last 355 miles of driving. Being a curious sort , Ry

an wondered how much fuel had been used in freeway driving (which takes on gallon for each 40 miles) Ryan started by guessing 6 gallons for the city driving , then completed the first row of the guess -and-check table below . Notice the failed check . Make your own guess and use it to fill in the next row of the table. city gallons 6 freeway gal 10 - 6 = 4 check city mi. 6(25) = 150 freeway mi. 4(40) = 160 total mi. 150 + 160 = 310 target 355 no Now write c in the city gallon column, fill in the remaining entries in terms of c, and set your expression for the total mileage equal to the target mileage Solve the resulting equation.

Mathematics
1 answer:
melisa1 [442]3 years ago
8 0
GAllon is ballon
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Jason agreed to make 12 payments of $38.50 to buy a new TV so far he has made Seven payments how much more money does Jason owe
Stolb23 [73]

Answer:

$192.50

Step-by-step explanation:

12*38.50=462

7*38.50=269.5

462-269.50=192.50

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Find only the rational roots of x4 – 9x3 + 16x2 + 18x – 36 = 0
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<span>x² - 18x - 4 = ox² - 18x = 4x² - 18x + (18/2)² = 4 + (18/2)²x² - 18x + 81

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The width of a rectangle is 3 meters less than the length period the perimeter is 14 meters. Find the width
beks73 [17]
The width of the rectangle is 2 meters
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3 years ago
What is the sign of −4ab when a&gt;0 and b&lt;0?
AVprozaik [17]

Answer:

A

Step-by-step explanation:

We have the expression:

-4ab

And we want to find its sign given that a>0 and b<0.

Notice that the expression is already negative since we have -4.

a>0 means that a is positive. Therefore, we can ignore it since it won’t do anything.

b<0 means that b is negative. Therefore, we will have two negatives being multiplied together. Hence, this will make a positive.

Therefore, the sign of our expression will be positive.

We can see this with an example. Let a=1 (1>0) and let b=-1 (-1<0). Then:

-4(1)(-1)=4

So, the sign is positive.

Hence, the answer is A.

7 0
3 years ago
A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
irga5000 [103]

Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0
3 years ago
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