If this is suppose to be 239%....
change to a fraction to look like this 238/100. This number cannot be reduced, so the common fraction is 239/100.
to make it a mixed number, you would simply divide 239 by 100. Your answer would come out to 2 with a remainder of 39. Put the remainder over the divisor and your answer for a mixed number will be 2 and 39/100.<span />
Answer:
C and E
Step-by-step explanation:
2^x + 1 = 5
2^x = 4
2^x = 2²
x = 2 , y = 5
(2,5) is the solution which lies in Quadrant 1
To find the answer convert 5 into 5/1. To make it compatible with 3/4 you have to have the same denominator. So to make 5/1 compatible with x/4 you multiply both sides by 4, so it would be 20/4. And then to find how many recipes you can make you would multiply 3 to the highest number it can be that does not exceed 20. The closest 3 can get to 20 before exceeding it would be 6 times. 6/1x3/4 =18/4. So you could make 6 recipes and you would have 2 pounds of potatoes left.
Zoe can make 6 recipies and she will have 2 pounds of potatoes left.
Answer:
What is meant by "bias due to selective survival" in cross-sectional studies?
First lets understand what is selective bias in cross-sectional studies. Basically its the bias that occurs when the random sample data for some analysis is selected in improperly. Such a selected sample is not able to represent the population that is to be analyzed. The reason is the improper randomization. So "bias due to selective survival" means that only the survival participants or survivors can be considered in this cross sectional studies. So if there is more probability of exposed cases to survive than unexposed cases or it could also be possible that unexposed cases have more probability to survive than exposed ones, so in either case the conclusion drawn from this cross sectional studies may differ from the proper cohort study. So the selective bias is introduced. Hence we can say that there is bias due to selective survival.
Step-by-step explanation:
Under what circumstances might there be no selective survival bias even if the selection probabilities are not all equal?
If the cross product of selection probabilities equals 1. Then there might be no selective survival bias even if the selection probabilities are not all equal. As we know that the cross product of odd ratio of selection probabilities is 1 means there is no relation between exposure and consequence or outcome and there is no bias in odd ratio.
Suppose that you could assess that the direction of possible selective survival bias in your study was towards the null. If your study data yielded a non-statistically significant odds ratio of 1.04, would it be correct to conclude that there was no exposure-disease association in your source population?
It would not be correct to conclude that there was no exposure-disease association in your source population because if the possible selective survival bias in the study was towards the null then this implies that the true odds ratio would be larger than 1.04. and therefore likely to be large and also differ statistically for the null value.
