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grandymaker [24]
3 years ago
7

Por favor!! Es urgente doy corona plis La edad de Pedro es tres veces la edad de Jorge, la suma de ambas edades es 72 años. Hall

e ambas edades.
Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

Pedro age =  54 ; Jorge age = 18

Step-by-step explanation:

Pedro age = P

Jorge age = J

3J = P

J + P = 72

we have to substitute the value of P in the second equation

J + 3J = 72

we have solve the equation

4J = 72

J = 18

we have to subistute this value in the first equation

3*18 = P

P = 54

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Answer:

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Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

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The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

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(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

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(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

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So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

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