Answer:
Witch Doctor
Song by Ross Bagdasarian Sr.
Explanation:
I instantly thought of Alvin and the Chipmunks!
When the nurse is reinforcing medication, the statement that she has to tell him should be apply the patch every morning and leave there for period of 12 to 14 hours, then remove it in the evening.
<h3>What is angina?</h3>
This is the condition that humans may have that would include very painful chest problems. The pain is usually severe. This pain would spread to the shoulder and other body parts. The reason would be poor circulation of blood.
<h3>What does it mean to reinforce medication?</h3>
This has to do with all of the ways that the nurse is going to ensure that there is medication compliance. It is necessary for people with health issues to adhere to taking their medications.
This would help to ensure that there is team based care that would last for only a period of time. It would help the patient to get better faster.
Hence the statement that has to be included when reinforcing medication would be: apply the patch every morning and leave there for period of 12 to 14 hours, then remove it in the evening.
Read more on angina here:
brainly.com/question/14358024
#SPJ1
Answer:
Yabure kabure no yabu isha ga take yabu
Explanation:
The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
brainly.com/question/13531044
Answer:
(15/17 = sin ∠ JLK)
(first option listed)
Explanation:
the "sin ∠ JLK" is what we can simply think of as the inside measurement of angle/corner L. (L is the letter in the middle of ∠ JLK , and if you imagine drawing a line from J to L to K, you would see that the only angle you formed both sides of is corner L)
so, we are looking for the sin of L.
(SOH CAH TOA)
we know that
sin = opposite / hypotenuse
However, we do not have the opposite value of this triangle <em>yet. </em>
-----
we can solve the length of the opposite side with the Pythagorean theorem:
a² + b² = c²
8² + b² = 17²
64 + b² = 289
- 64 - 64
b² = 225
√b² = √225
b = 15
----
so, to solve for sin L,
(sin = opposite / hypotenuse)
we should divide the opposite (15) over the hypotenuse (17)
so, 15 / 17 = sin L
(15/17 = sin ∠ JLK)
