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Usimov [2.4K]
3 years ago
14

Conditionals: Photo attached

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

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an oil company drilled several walls.fifty wells, or 25%,produced oil.what was the total number of wells that were drilled
Phantasy [73]
25% is equal to 100/25=1/4

We can substitute this into an equation to get the total number of wells where n can be equal to the total number of wells.

1/4*n=50
n/4=50
n=50*4
n=200

The total number of wells that were drilled was 200.
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2 years ago
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Is this a function or no
makkiz [27]
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4. Choose the best answer.
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the answer isexistence
4 0
2 years ago
Which statement below about roots is false.Immersive Reader (5 Points) Simplified radicals have a positive and a negative root.
scoray [572]

Answer:

Statement (B)

Step-by-step explanation:

Which statement below about roots is false?

Let's arrange the statements by assigning option-letters a, b, c, d to them.

(A) Simplified radicals have a positive and a negative root.

This is true, as the root of any number is either a positive or a negative; especially if the rooting index is an even number like 2 or 4. For example, the square root (when the index is 2) of 9 is either +3 or -3. To check, find their squares. +3 x +3 = 9 and -3 x -3 = 9.

(B) A radicand is the symbol used when working with roots.

This statement is false, as the name for the symbol used in root operations is "radical symbol". A radicand is the number or expression whose roots are about to be found. It is the expression that lies under or inside the radical symbol!

(C) Exponents and Roots are inverses.

Exponents are the powers to which mathematical expressions are raised. Roots are the indexes by which mathematical expressions are divided. Exponents are hence the opposites or inverses of roots.

(D) Roots can be squared, cubed, quadrupled, or raised to higher powers.

Yes! The root of a mathematical expression or figure can be raised to any number or power, be it 2 (square), 3 (cube), 4 (quadruple), 5 (quintuple) or 100 (cent).

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%
Llana [10]

a) The given function is

f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}

The domain refers to all values of x for which the function is defined.

The function is defined for

x^4+x^3-4x^2-4\ne0

This implies that;

x\ne -2.69,x\ne 1.83

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

x^4+x^3-4x^2-4=0

This implies that;

x= -2.69,x=1.83

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

\frac{x^2-4}{x^4+x^3-4x^2-4}=0

\Rightarrow x^2-4=0

x^2=4

x=\pm \sqrt{4}

x=\pm2

The roots are x=-2,x=2

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

x=0 into the function

f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}

f(0)=\frac{-4}{-4}=1

e) to find the horizontal asypmtote, we take limit to infinity

lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0

The horizontal asymtote is y=0

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is  at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0
2 years ago
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