Answer: Our required probability is 0.83.
Step-by-step explanation:
Since we have given that
Number of dices = 2
Number of fair dice = 1
Probability of getting a fair dice P(E₁) = 
Number of unfair dice = 1
Probability of getting a unfair dice P(E₂) = 
Probability of getting a 3 for the fair dice P(A|E₁)= 
Probability of getting a 3 for the unfair dice P(A|E₂) = 
So, we need to find the probability that the die he rolled is fair given that the outcome is 3.
So, we will use "Bayes theorem":

Hence, our required probability is 0.83.
Answer:
x= 20 x =-5
Step-by-step explanation:
x^2 – 15x – 100 = 0.
What two numbers multiply to -100 and add to -15
-20 * 5 = -100
-20 +5 = -15
(x-20) (x+5) =0
Using the zero product property
x-20 =0 x+5 = 0
x= 20 x =-5
Answer: three sets of value show 3 consecutive increases and they could be the intensities during fourth, fifth, and six visits:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Explanation:
1) The program recommends a constant intensity for 3 visits, which is what the table shows:
Day Intensisty
1 63%
2 equal ⇒ 63%
3 equal ⇒ 63%
2) Hence, you have to determine the valid sets that meet the recommendation for the fourth, fifth, and six visits, which are the next three.
2) For the next three visits, the program recommensd increasing intensities.
There are three options that show 3 consecutive increases; they are:
- 66%, 69%, 72%;
- 63%, 65%, 67%, and
- 67%, 72%, 77%
Therefore, those are the choices that apply.
Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
Let's simplify step-by-step.
<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b2
</span></span></span>There are no like terms.
Answer:
<span>=<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b<span>2</span></span></span></span></span>