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vova2212 [387]
3 years ago
7

Convert 120 Ibs to kilograms

Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

54.431 kilograms

Step-by-step explanation:

don't have step by step but 1kg is 2.205lbs

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Simplify the following expression.<br> ​<br> ​ 15p+15p+25p =​
IrinaK [193]

​ 15p+15p+25p=​30p+25p=55p

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6 and half minus seven-eighths divided by five and eleven-sixteenth=
kow [346]
The answer is 90/91. 6 1/2 - 7/8 divided by 5 11/16. Turn 6 1/2 and 5 11/16 to an improper fraction. 6 1/2= 13/2. 5/11= 91/16. Then you have to get each fraction to have equal denominators. All of them can have a denominator of 16. So you times everything to get a denominator of 16. 13/2= 104/16. 7/8=14/16. 91/16 stays the same because the denominator is already 16. Next you subtract 104/16 and 14/16 and get 45/8.( because you need to put it in simplest form.) Lastly you divide 45/8 by 91/16 and get 90/91.

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What 2 numbers have a total of 46 and a diffrence of 12​
aleksley [76]

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29 and 17

Step-by-step explanation:

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2 years ago
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How many cylinder containers that are the same height and have the same base area would these three henna cones fill up?
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3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
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