A ball is thrown from an initial height of

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

Answer:

Step-by-step explanation:

If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:

$11=-5t^2+30t+1$ and

$0=-5t^2+30t-10$ and factor this however it is you are factoring in class to solve for t to get

t = .35 seconds and t = 5.6 seconds

Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.

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