A ball is thrown from an initial height of
1 answer:
Answer:
Step-by-step explanation:
If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:
and
and factor this however it is you are factoring in class to solve for t to get
t = .35 seconds and t = 5.6 seconds
Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.
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Answer:
The answer is : x = 9.505 and x = -1.005
Step-by-step explanation:
To solve the quadratic equation use the formula :
Where a is the coefficient of x² , b is the coefficient of x and c is the numerical term
∵ a = 18 , b = -153 and c = -172
∴
∴ x = 9.505 and x = -1.005