A ball is thrown from an initial height of
1 answer:
Answer:
Step-by-step explanation:
If we are looking for the times that the ball was 11 meters off the ground, we sub in 11 for the height on the left and solve for t:
and
and factor this however it is you are factoring in class to solve for t to get
t = .35 seconds and t = 5.6 seconds
Because the ball reaches this point in its way up and then passes it again on its way down, the ball will have 2 times at this height.
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Answer:
y=4x
Step-by-step explanation:
First, find the slope
We know 2 points, (2,8) and (12,48).
(2,8) can be (x1, y1)
(12,48) can be (x2, y2)
We can say that y2 is 48, y1 is 8, x2 is 12, and x1 is 2. Substitute them in
m=4
Now, we can use the point slope formula, since we have a point and the slope
We know m, the slope is 4. We also know a point (2,8), which is (x1, y1). Substitute them in
y-8=4(x-2)
Distribute the 4
y-8=4*x-2*4
y-8=4x-8
Add 8 to both sides
y=4x