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2 years ago

A segment has the following coordinates A(6, 7), B(4, -3). Find the coordinates of the midpoint of segment AB

Mathematics

2 answers:

raketka [301]2 years ago

4 0

Answer:

i think that would be (5,2)

Tpy6a [65]2 years ago

3 0

Answer:

(5,2)

Step-by-step explanation:

A(6, 7), B(4, -3)

the mid point has the coordinates

x coordinate is ( 6+4)/2 = 10/2=5

y coordinate is (7 + -3)/2 = 4/2=2

The midpoint of the line segment AB is the point with the coordinates (5,2)

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3(x - 2) + 48 = -3x

kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

8 0

3 years ago

B.HELPPPP MEEEE PLSSSS AND THANK YOUU

Gemiola [76]

Answer:

A. (3, 8) and $2\sqrt{2}$

B. (2, 4) and $2\sqrt{10}$

Step-by-step explanation:

Midpoint formula: $(\frac{x1+x2}{2} ,\frac{y1+y2}{2})$

Distance formula: $\sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }$

A. plug in the points in the formulas

(4, 7) and (2, 9)

Midpoint:

$(\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)$

Length:

$\sqrt{(2-4)^2+(9-7)^2}=\sqrt{4+4} =\sqrt{8} =2\sqrt{2}$

(5, 5) and (-1, 3)

Midpoint:

$(\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)$

Length:

$\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}$

Can you consider marking my answers as brainliest lol it would mean a lot. Hope this helped.

4 0

1 year ago

The secret number has a 7 in the ones place. The tens number is an odd number

Lana71 [14]

This really is left up to you as long as you have an odd number in the tens place and a 7 in the ones place. How big (or small) the number is is up to you. As long as it is at least 17, it's pretty much up to you.

7 0

2 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$

Hence, the correct answer is option A) 1260

5 0

3 years ago

What are the angles of rotational symmetry?

bulgar [2K]

Answer:

A figure has rotational symmetry if it can be rotated by an angle between 0° and 360° so that the image coincides with the preimage.

Step-by-step explanation:

4 0

3 years ago

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