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Gnom [1K]
3 years ago
13

A segment has the following coordinates A(6, 7), B(4, -3). Find the coordinates of the midpoint of segment AB

Mathematics
2 answers:
raketka [301]3 years ago
4 0

Answer:

i think that would be (5,2)

Tpy6a [65]3 years ago
3 0

Answer:

(5,2)

Step-by-step explanation:

A(6, 7), B(4, -3)

the mid point has the coordinates

x coordinate is  ( 6+4)/2  = 10/2=5

y coordinate is (7 + -3)/2 = 4/2=2

The midpoint of the line segment AB is the point with the coordinates (5,2)

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What is the exponential expression for the numerical expression ​14⋅14⋅14⋅14​?
SVEN [57.7K]

It may be 1^4 ............................

7 0
3 years ago
Solve for the variable x - 9 = 11
Strike441 [17]

Answer:

20

Step-by-step explanation:

x - 9 = 11

+9         +9

x = 20

3 0
3 years ago
Read 2 more answers
Hello Help Plis…………..
Lostsunrise [7]

Answer:

7. 20 + 5 + 3/10 + 6/100

8. 7 + 4/10 + 2/100 + 5/1000

Step-by-step explanation:

We are writing two numbers in expanded form, to help, we can use the guide above both numbers. Expanded form is all about breaking apart a number by place value and putting them in an additional sequence.

Let's look at 7, 25.36.

There are the tens, ones, tenths, and hundredths place being used, therefore :

20 + 5 + 3/10 + 6/100

We can do the same for 8, 7.425.

There are ones, tenths, hundredths, and thousandths being used, therefore :

7 + 4/10 + 2/100 + 5/1000

8 0
3 years ago
Select the list that correctly includes all of the coefficients from the problem
matrenka [14]

Answer:

( B.) 6, 1, -2 , -4

Step-by-step explanation:

A coefficient is a number multiplied by a variable. So, in this case let's take a look at the problem.

-2+6y+m-2y+8-4m

Now we have to find the numbers that have a variable next to it

which are 6,m,-2, and -4

(If you are wondering that why m is a coefficient its because it is also known as 1m)

Final answer = 6, 1, -2 , -4

Hope this helps!

7 0
3 years ago
The intercepts of the circle (x-1)^2 + (y-2)^2 = 10 are ?
IRISSAK [1]

y-intercept:  Let x = 0 and solve for y:

(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10

                                =>  1 + y^2 - 4y + 4 = 10, or   y^2 - 4y  -5 = 0

                                The solutions of this quadratic are y = 5 and y = -1.

                                Thus, the y-intercepts are (0, 5) and (0, -1).

Now find the x-intercepts:  Let y = 0 and solve the resulting equation for x:

(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.

Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:

                                                  x = 1 +√6 and x = 1 - √6, so that the x-intercepts

                                                  are (1+√6, 0) and (1-√6, 0).

8 0
3 years ago
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