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Travka [436]
2 years ago
14

A house is on an 80,000 square foot lot. About how many acres is the lot?

Mathematics
2 answers:
mixas84 [53]2 years ago
3 0

Answer:

There

Step-by-step explanation:

mark me brainliest!!

Andreas93 [3]2 years ago
3 0

Answer:

1.836 acres

Step-by-step explanation:

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The area of a rectangular patio is (12x - 4) square units. What are possible dimensions of the patio?
MAVERICK [17]
You need two terms that multiply to (12x-4). The term on the outside needs to be a common multiple of 12 and 4. The common factors are 1, 2, and 4. Here are the following possible dimensions:
1(12x-4)
2(6x-2)
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4 0
3 years ago
4x + 4y + 2z = 8
Vikentia [17]
The answer is no, because the first two equations are right but the third equation equals -16 instead of -15. So the answer is no (2,-2,4) is not the solution to all the system of equations.
5 0
3 years ago
What is the value of x?
Akimi4 [234]
(2x + 2) = (3x + -52)

Reorder the terms:
(2 + 2x) = (3x + -52)

Remove parenthesis around (2 + 2x)
2 + 2x = (3x + -52)

Reorder the terms:
2 + 2x = (-52 + 3x)

Remove parenthesis around (-52 + 3x)
2 + 2x = -52 + 3x

Solving
2 + 2x = -52 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
2 + 2x + -3x = -52 + 3x + -3x

Combine like terms: 2x + -3x = -1x
2 + -1x = -52 + 3x + -3x

Combine like terms: 3x + -3x = 0
2 + -1x = -52 + 0
2 + -1x = -52

Add '-2' to each side of the equation.
2 + -2 + -1x = -52 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = -52 + -2
-1x = -52 + -2

Combine like terms: -52 + -2 = -54
-1x = -54

Divide each side by '-1'.
x = 54

Simplifying
x = 54
4 0
3 years ago
Hi, can you please do these? thanks for helping!​
arlik [135]

Answer:

i will answer you other if u rate me brainliest

4 0
3 years ago
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Identify the dollar amount due on a sample of 49 credit cardsModeMedianmean
Anvisha [2.4K]

Given:

Identify the dollar amount due on a sample of 49 credit cards.

The amount due on the next payment is any one of the averages that mode,median or mean can be used.

5 0
1 year ago
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