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2 years ago

7

Point give away. enjoy 5 more questions

1 answer:

Anettt [7]2 years ago

6 0

Answer:Thanks!

Step-by-step explanation:

You might be interested in

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}$

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7$

8 0

2 years ago

Read 2 more answers

I need some help with this

masya89 [10]

Answer:

A, C, D

Step-by-step explanation:

Consider triangles NKL and NML. These triangles are right triangles, because

$m\angle K=m\angle M=90^{\circ}$

In these right triangles:

$\overline{NL}\cong \overline {NL}$ - reflexive property;
$\angle KLN\cong \angle MLN$ - given

Thus, triangles NKL and NML by HA postulate. Congruent triangles have congruent corresponding parts, so

$\overline{KN}\cong \overline{NM}\\ \\\overline{KL}\cong \overline{LM}\ [\text{option D is true}]$

Since

$\overline{KN}\cong \overline{NM},$

then

$7x-4=5x+12\\ \\7x-5x=12+4\\ \\2x=16\\ \\x=8\ [\text{option A is true}]\\ \\MN=KN=7\cdot 8-4=56-4=52\ [\text{option C is true}]$

Option B is false, because KN=52 units.

Option E is false, because LN is congruent KN, not LM

4 0

2 years ago

Lenny rolls two number cubes. What is the probability that the sum of the numbers Lenny rolls is either 4 or 7?

Mashutka [201]

Probability of an event =

(number of ways the event can happen) / (total number of possible outcomes) .

Well, the total number of possible outcomes is easy. It's

(6 possibilities for the first cube) x (6 possibilities for the 2nd cube)

= 36 total possible ways for two cubes to roll.

Now, how many of those possibilities show either 4 or 7 ?

Well, here's how a 4 can come up:

1 . . . 3

2 . . . 2

3 . . . 1

and here's how a 7 can come up:

1 . . . 6

2 . . . 5

3 . . . 4

4 . . . 3

5 . . . 2

6 . . . 1 .

So there are 9 ways all together for Lenny to be successful.

The probability is (9/36) .

That's 1/4 , or 25% .

7 0

2 years ago

Read 2 more answers

Is 51x51 is even or odd

AURORKA [14]

You can predict that it's odd because the end of the 2 numbers is 1 and 1 x 1 is 1 and one is an odd number. (answer is odd)

3 0

2 years ago

Read 2 more answers

A parabola has zeros at (5,0) and (-3,0) and passes through point (6,18) determine the axis of symmetry

worty [1.4K]

Answer:

The axis of symmetry is $x=1$

Step-by-step explanation:

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

In this problem we have a vertical parabola open upward

The x-coordinate of the vertex is equal to the midpoint between the zeros of the parabola

so

$x=\frac{5-3}{2}=1$

therefore

The axis of symmetry is $x=1$

5 0

3 years ago